Search:

Type: Posts; User: mcwang719

Page 1 of 3 1 2 3

Search: Search took 0.02 seconds.

  1. ok. so are a and b correct? I was thinking if I...

    ok. so are a and b correct? I was thinking if I plugged in t=3 into the first equation to get u. then put that value into 3.6-0.06u=a.

    So u= (3.6/.06)(1-e^(-.06*3))+45e^(-0.06*3)) to get...
  2. sorry i messed up on the math. I did it again and...

    sorry i messed up on the math. I did it again and got t=18.31 as well. So are my other steps correct I know now that I have to plug in 18.31 instead of 1.78, so if I make those corrections will the...
  3. b) used the first equation. and plugged in the...

    b) used the first equation. and plugged in the numbers 55= (3.6/.06)(1-e^(-0.6t) +45e^(-.06t) and got t=1.78 seconds

    Then used the answer to to get a) plugged t into equation 2....
  4. Distance, Velocity, and Acceleration of a vehicle

    The acceleration of a vehicle takes the form du/dt =3.6 - 0.06u where u is the vehicle speed in ft/sec. The vehicle is traveling at 45 ft/sec at time T.

    a) Determine the distance traveled by the...
  5. Replies
    6
    Views
    1,329

    Can you explain this to me I know R X R is the...

    Can you explain this to me I know R X R is the cartesian product, but I'm having trouble applying it to this problem
  6. Replies
    6
    Views
    1,329

    Equivalence relations

    For the following relation indicate whether it's reflexive, symmetric, or transitive?
    R, where (x,y)R (z,w) iff x+z less or equal to y+w, on the set real numbers X real numbers.

    Looking at this...
  7. Clarification on a proof: ...Prove m=b iff a|b

    Hi I'm working on a proof I have the solution but don't understand it fully. The problem is:

    Let a and b be natural numbers and LCM(a,b)=m. Prove that m=b if and only if a divides b.
    Proof:...
  8. Thank you very much Daon I really appreciate it!...

    Thank you very much Daon I really appreciate it! You have been extremely helpful!
  9. Yes you need commutativity of H to be a group. So...

    Yes you need commutativity of H to be a group. So if G is non-abelian than, than H is not a subgroup?
  10. There are two parts to this question. Prove or...

    There are two parts to this question. Prove or Disprove:
    a) H is a subgroup of G
    b) If G is abelian, H is a subgroup of G

    I'm a little confused, so I just proved a) and how is proving b) any...
  11. Sorry let me rephrase that. What I got from the...

    Sorry let me rephrase that. What I got from the book is we assume a and b belong to H. This means a^2=e and b^2=e and we must show that (ab^-1)=e.

    So (ab^-1)^2= ab^-1ab^-1= a^2(b^-1)^2=...
  12. Replies
    3
    Views
    862

    Thanks Pka! That helped out a lot. Can you give...

    Thanks Pka! That helped out a lot. Can you give me some pointers to show H is equal or less than N(H).
  13. so can we say a^2=e and b^2=e so (ab^-1)=e. So...

    so can we say a^2=e and b^2=e so (ab^-1)=e. So (ab^-1)^2= ab^-1ab^-1= a^2(b^-1)^2= (a^2)(b^2)^-1= ee^-1= ab^-1.
  14. Replies
    3
    Views
    862

    Show H is equal or less than N(H).

    Let G be a group and let H be a subgroup of G.

    N(H)={x belongs G / xHx^-1 = H}
    a)Show that H is equal or less than N(H).
    b) Prove that N(H) is a subgroup of G.

    To be honest I'm completely...
  15. Replies
    11
    Views
    2,487

    Ok after reading the book I finally think I got...

    Ok after reading the book I finally think I got it! U(14) is cyclic because it has the generators <3> and <5>.
    <3>={1,3,9,13,11,5} (has all the elements)
    <5>={1,5,11,13,9,3}
    <9>={1,9,11} (doesn't...
  16. Replies
    11
    Views
    2,487

    What I did was I followed your example on U(6),...

    What I did was I followed your example on U(6), so in U(14), 13^0=1, 13^1=13 and so on. Isn't that what you showed in your example with U(6)? Thanks.
  17. Replies
    11
    Views
    2,487

    Ok so I think I understand U(14) is cyclic...

    Ok so I think I understand U(14) is cyclic because U(14)=<13>={13^0,13^1,13^2...}={1,13}=U(14). Is that correct? thanks
  18. Replies
    11
    Views
    2,487

    So all the elements raised to the 6th power gives...

    So all the elements raised to the 6th power gives the identity. Is that what you mean?
  19. Replies
    11
    Views
    2,487

    So could I say U(14) is cyclic because 1*3 mod...

    So could I say U(14) is cyclic because 1*3 mod 14=3, 3*5 mod 14=1, 5*9 mod14=3, 9*11 mod 14=1, 11*13 mod 14=3? Would this be enough to show that it's cyclic? Thanks.
  20. Replies
    11
    Views
    2,487

    Determine whether or not U(14) is cyclic.

    Determine whether or not U(14) is cyclic. Justify your answer.

    I'm having some trouble with this problem. So U(14) = {1, 3, 5, 9, 11, 13}. Do I simplify need to find a generator? (If there is a...
  21. Thanks unco!!! you've been very helpful.

    Thanks unco!!! you've been very helpful.
  22. it doesn't state that it equals 2(beta) i kinda...

    it doesn't state that it equals 2(beta) i kinda assumed because (beta)(beta)^-1= 2m right??
  23. How does (beta)(beta)^(-1) equal 2(beta)?

    Hello this problem is from my modern algebra class.

    Let (alpha) and (beta) belong to S(sub n). Prove that (beta)(alpha)(beta)^-1 and (alpha) are both even or both odd.

    I got the answer but...
  24. i got it!!!! i reread you're last paragraph and...

    i got it!!!! i reread you're last paragraph and finally got it A^4= identity. yay!!!! thanks everyone.
  25. Can you explain how |A|=4? Thanks!

    Can you explain how |A|=4? Thanks!
Results 1 to 25 of 69
Page 1 of 3 1 2 3