Haemophilia is a sex-linked genetic disease that results in the inability of blood to clot. (A disease is sex-linked if the disease gene is located on X-chromosome.) A woman with one copy of the gene...
Type: Posts; User: mammothrob
Haemophilia is a sex-linked genetic disease that results in the inability of blood to clot. (A disease is sex-linked if the disease gene is located on X-chromosome.) A woman with one copy of the gene...
Im having some trouble getting the answer to this promlem...
Find the general solution to the given differetial equation. Derive your trial solution using the annihilator technique.
\[...
Determine the region in the xy-plane for which
(1+y^3)y' = x^2
This has a unique solution.
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Not really understanding what this is asking of me?
haha.... its funny how easy things can end up being. thanks.
Im having a little issue figuring out this intial value problem.
Solve the Initial Value Problem
y' = (3x^2)/[(3y^2)-4] where y(0)=1
Looks like I can solve it as a seperable DE.
dy/dx...
does the real spectral theorem have anything to do with this?
For which real numbers c and d does the matrix have real eigenvalues and three orthogonal eignvectors?
120
2dc
053
I have some thoughts on this but have not gotten too far.
The matrix in...
I avoided math through highschool and held off from taking it as long as I could, until I had to start the calculus series for a computer sci major. After Second semester calculus I change my major...
yesss...
I see it now. I was missing the concept between standard and non-standard bases. Much appreciated.
The matrix A is the matrix relative to B and B'.
I mean if you Multiply A with coordinate matrix relaitve to B you get a coordinate matrix relative to B'
T:R2 -----> R3
\begin{array}{l}
T(x,y) = (x + y,x,y) \\
B = \{ (1, - 1),(0,1)\} \\
B' = \{ (1,1,0),(0,1,1)(1,0,1)\} \\
\end{array}
The matrix for T relative to B and B' is
T: P3 ----> P4
\begin{array}{l}
T(ax^3 + bx^2 + cx + d) = (3x + 2)(ax^3 + bx^2 + cx + d) \\
B = \{ x^3 ,x^2 ,x,1\} \\
B' = \{ x^4 ,x^3 ,x^2 ,x,1\} \\
\end{array}
Find the...
Prove that the orthogonal complement of a subspace of (Rn) is itself a subspace of (Rn)
-----------------------------------------------------
Let V be the orthogonal complement of S, S a...
I think I missed something before... they book probably is refering to 3 space. I was just asumming for some reason that the vector triple product was used for vectors larger than ordered triplets. ...
thats how I did it... for u v w being ordered triplets. (R3)
But does that truely prove that it works for (Rn)?
Or do i need to do it somehow like this...
u = (u1, u2, u3, ... un) ...
Im trying to prove this identity.
Let u v and w be vectors in (Rn) and <u,u> denote the dot product.
u x ( v x w ) = <u,w> v - <u,v> w
Here are my ideas on this.
I tried using the...
Im stuck on this proof.
Let A and B be nxn matricies such that AB is singular. Prove that either A or B is singular.
Sooooo, here we go.
Let M = AB where is M is the given singular matrix....
Im doing a LU factorization on Matrix A
A = \left[ {\begin{array}
1 & 1 & 1 \\
1 & 2 & 2 \\
1 & 2 & 3 \\
\end{array}} \right]
I reduced it to an upper triangular matricie
This proof is looking kinda weird to me. Does this look correct?
Let (A) be a nonsingular invertable matrice.
(I) is the identity matrix
If A(A)=A, the prove that A=I
\begin{array}{l}
so I have my solution equations, which represent an infinite amount of solutions.
x + z + 3w = -1
y - 2z = 5
so to write my answer in a parametric form would this be correct?
Let z and y...
When you do elementry row operations, do you see the matrix in columns or in rows?
I have been seeing this in rows so far, trying to get a leading one at the begining and then trying to get...
soooo... I have these four equations and need to solve for four unknowns.
So I built a 4x5 matrix for it. Im useing (r1234) to denote the rows and bold font to seperate decemal numbers where they...
Thanks... I have my calc III final tomorrow and that was an example on our review handout. It was freaking me out a little.
...............Back to studying.................
well this is whats going on if I interpreted your problem right
\frac{{2^{ - 3} + 4^{ - 1} }}
{{2^{ - 3} }} = \frac{{\frac{1}
{{2^3 }} + \frac{1}
{{4^1 }}}}
{{\frac{1}
{{2^3 }}}}
27^{2/3} = \sqrt[3]{{27^2 }}
when you have a constant or vaiable raised to a fration like above the denominator of the fraction becomes the index and the numerator hangs on to the constant or...