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    Re: Complex Numbers: 4x^2 + 1 = 0

    Thank you.
    John Whitaker
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    Re: Complex Numbers: 4x^2 + 1 = 0

    I''m sorry... I can do many problems in complex numbers, but I have not seen one structured like this one. I learn not by reading complicatiions, but by following similar examples step by step.
    ...
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    Re: Complex Numbers

    Only instruction is to "Solve these equations>"

    "Hornsby, Lial, & McGinnis" 8th Ed.
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    Complex Numbers: 4x^2 + 1 = 0

    My instructor likes to create problems for which there are no examples or similar problems in our text we might refer to for clarity. So I need to learn how to deal with:

    4x^2 + 1 = 0
    4x^2 ...
  5. Re: Completing the Square

    I think I get it. Thank you.
  6. Completing the Square: 2x^2 + 12x + 3 = 0

    I have:

    2x^2 + 12x + 3 = 0 (divide by 2)
    x^2 + 6x + 3/2 = 0
    x^2 + 6x = - 3/2
    X^2 + 6x + 9 = 15/2
    (x + 3 )^2 = 15/2
    x + 3 = +/- sqrt (15/2)
    x + 3 ...
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    Re: Simplifying a string.

    Thank you.
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    Simplifying a string.

    I get just so far before becoming confused.

    2 [ 5 - ( - 3 ) ] - 2 ( - 3 - 4 )
    2 [ 5 + 3 ) - 2 ( - 7 )
    2 ( 8 ) - 2 ???

    Minus 2 x minus 7 (or is it a plus 7 ?)
    I can't be certain, and I have...
  9. Re: Rationalizing Denominators w/ Cube Roots

    I'll try to figure it out, though I don't recall anything in my text that relates to the assignment or that exponent. I'll look again.
    Thanks
    John Whitaker
  10. Rationalizing Denominators w/ Cube Roots

    I donít (yet) know how to illustrate the radical has an index, so I wrote it in. Perhaps I am about to learn. However,

    index=4 sqrt 5x / z = index=4 sqrt 5x / index=4 sqrt z * index=4 sqrt z^3...
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    Re: Completing the square

    Gentlemen,
    I do appreciate your efforts... and I'll study what you have shown me, though it still is not as clear as I require (not your fault). I won't post to this again. Thank you.
    John Whitaker
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    Re: Completing the square

    Somewhere my problem has been turned around and solutions are being given to the part I understand. Iíll begin again. Please be patient. I canít move ahead until I understand this

    K^2 + 5K -1 ...
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    Re: Completing the square

    Denis, Thanks, I'll try it. Don't give up.

    Mark, Thanks. k(k+5/2) = k^2 + 25/4 yes... no...?
    WAIT! I think I'm getting it...! I have been forgetting to add the k to the 5/2 part of the...
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    Re: Completing the square II

    I thank you for your input, but I'm not smart enough to grasp it. I worked it out substituting the numbers and it did not clarify my problem.

    I will appreciate it if, using the numbers I...
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    Completing the square II

    I' m sorry... I thought I could figure it out from the responses to my first submission, but I can't. The hang up is that k^2 + 5k + 25/4 = 29/4.

    The next step is (k + 5/2)^2. I don't see...
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    Re: Completing the square

    I' m sorry... I thought I could figure it out from the responses, but I can't.

    (k + 5/2)^2 returns k^2 + 25/4... not k^2 + 5k + 25/4 that I had going in.

    Where is the middle term? I'm...
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    Re: Completing the square

    Denis,
    I'm still struggling... hope this is the last semester. Thanks. (You haven't qiven up either).
    John

    Gentlemen,
    Thank you and I wish you a great holiday.
    John
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    Completing the square

    The problem:
    Solve k^2 + 5k -1 = 0

    k^2 + 5k = 1
    k^2 + 5k + 25/4 = 4/4 + 25/4
    k^2 + 5k + 25/4 = 29/4

    The next step my text displays is (k+5/2)^2 = 29/4 without telling me how it arrived at...
  19. Re: Radical Expressions: 2 sqrt 75/16 + 4 sqrt 8/sqrt32

    I think I have it. Thank yoy.
    John Whitaker
  20. Re: Radical Expressions: 2 sqrt 75/16 + 4 sqrt 8/sqrt32

    I'm sorry... still don't get it. Can you show me where I am to do this?
    Thank you.
    John Whitaker :wink:
  21. Radical Expressions: 2 sqrt 75/16 + 4 sqrt 8/sqrt32

    The problem and book solution is:

    2 sqrt 75/16 + 4 sqrt 8/sqrt32
    = 2 sqrt 25*3/sqrt 16 + 4 sqrt 4*2/sqrt 16*2
    = 2(5 sqrt 3/4) + 4(2 sqrt 2/4 sqrt 2)
    = 5 sqrt 3/2 + 2
    = 5 sqrt 3/2 ...
  22. Re: Rational Exponents

    Thank you, Denis...

    Another: My text, Lial, Hornsby, et al, assumes I know more than I do and takes leaps over steps I need. I get down to:

    X^-8/3-4/3 Y^4-(-2/9)

    and I don't understand how...
  23. Re: Rational Exponents

    Loren,
    Makes sense. Thank you.
    John Whitaker
  24. Rational Exponents: write Y^10 under radical as exponential,

    It's been a while, and I forgot how to express a radical.

    Instruction: Write each radical as an exponential and symplify.
    Problem displays Y^10 under a radical. Answer given is Y^5. What are the...
  25. Re: A Paradox

    Thank you.
    Signing out.
    John W
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