IceViper777
New member
- Joined
- Sep 19, 2005
- Messages
- 1
Hey I found this site by looking for help with this problem.
If a polygon has exactly 65 diagonals, how many sides must it have.
What I know now...
n(n-3)/2
thats a divison thing n(n-3) divided by 2. That's the formula for finding the exact amount of diagonals in a certain sided shape.
1 2 3 4 5 6 n
X X 0 2 5 9 N(N-3) / 2
I know this has to be reversed, but it just hurts my head to think about it.
Thanks for the help in advance... This is a very good idea for use of bandwith!
If a polygon has exactly 65 diagonals, how many sides must it have.
What I know now...
n(n-3)/2
thats a divison thing n(n-3) divided by 2. That's the formula for finding the exact amount of diagonals in a certain sided shape.
1 2 3 4 5 6 n
X X 0 2 5 9 N(N-3) / 2
I know this has to be reversed, but it just hurts my head to think about it.
Thanks for the help in advance... This is a very good idea for use of bandwith!