can you plez see if i did this right?

OLOLlion13

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Joined
Sep 19, 2005
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15
Ok so its translate each probelm into an equation and then solve.

(1) the hight of a tower is 3 times the height of a certain building

equation- h=3*H

(2) IF THE HIEGHT OF THE TOWER IS 50m TALLER THAN THE BUILDING. THEN HOW TALL IS THE TOWER.

equation- 50m*3=b

problem-

50m*3=150m

would that be right but is there another way to do that?
 
Let the height of the building be , h.

Then the height of the tower is 3 h.

If the tower is 50m higher than the building.

Then

h + 50 = 3h


Solve this for h, the height of the building, then find the height of the tower.
 
ok so then you have to get h by its self right?

and you do that by doing this

h+50m=3h
h=3h-50

right
 
Hmm


Its not just getting, h, by itself its getting all the h's on one side of the equation.

You can do that by taking, h, from the left hand side.

h + 50 = 3h

50 = 3h

Just like that, but wait

WHAT WE DO TO ONE SIDE WE MUST DO TO THE OTHER SO WE MUST TAKE, h, FROM THE OTHER SIDE ALSO, right.

50 = 3h - h

Can you simplify and find h?

Sorry about all those edits.
 
so then that would be

3h-h=50
2h=50
h=50/2

so then that comes out to 25 is that right?

but how would you check that?
 
Well we have to hope the original equation is correct.

You can check your solution by substituting.

h + 50 = 3h

So the building is 25 m and the tower is 75 m.

The tower = the building + 50 = 3 times the height of the building.

The tower is both 3 times the height of the building and 50m taller. Must be right?!

Anyway you can check back later to see if you get anymore responses.
 
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