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Thread: BODMAS AND SIMPLIFYING AN EXPRESSION

  1. #1
    New Member
    Join Date
    Sep 2005
    Location
    NC
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    BODMAS AND SIMPLIFYING AN EXPRESSION

    Here is my current matter at hand. The problem below ask me to simplify it and I have no real background with using the B of BODMAS method so I would like you to check out what I have and maybe offer some assistance if you will. Here we go.

    5[3(2x-2)+3]
    =3(x)+3
    =6x(5)
    =11x

    Now this is what I have and I was wondering if I could please get some feedback and direction from someone.
    Thanks,
    watcjpp

  2. #2
    Guest
    5[3(2x-2)+3]


    the 2x-2 cannot be made to equal x

    3(2x-2)= 6x -6

    then use this back in your equation

    5( (6x-6) +3)

    = 5( 6x-3)
    =30x -15

  3. #3
    New Member
    Join Date
    Sep 2005
    Location
    NC
    Posts
    23
    Thanks because I could not find anything that was even close to explaining these operations. I was really thrown off by the Bracket and well I was trying to figure it out.

    Again Thanks.

    so here we go
    5[3(2x-2)3]
    3(2x-2)=6x-6
    5((6x-6)+3)
    =5(6x-3)
    =30x-15
    Again thanks for the direction once again my headache has been lessened and I learned something new.

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