orchidpsycho
New member
- Joined
- Sep 26, 2005
- Messages
- 41
The problem asks find the x and y intercepts of the graph of the equation
y=x^2-5x+6
for the y I got
y=(0)^2-5(0)+6
y=6
(0,6)
On the x do i factor?
0=(x-5)(x-1)
5=x
1=x
(5,0) (1,0)
Not sure if thats what I do or not? any help would be appreciated.
y=x^2-5x+6
for the y I got
y=(0)^2-5(0)+6
y=6
(0,6)
On the x do i factor?
0=(x-5)(x-1)
5=x
1=x
(5,0) (1,0)
Not sure if thats what I do or not? any help would be appreciated.