Please Help/Verify

rgeer

New member
Joined
Sep 14, 2005
Messages
32
Hello,

I have a few questions that I need help on and also verifying these problems:

1)There are 4 entrances to a building, 3 escalators up, 2 esclators down. How many ways can a person enter from outside, go to the second floor, return to the first floor, then leave the building?

I believe you would do 4x3x12=24 ways.

2) A six-sided die and a fair coin are tossed together. How many outcomes are in the sample space?
I believe its 8 outcomes.

Thanks in advance,
Ryan
 
Hello, Ryan!

1)There are 4 entrances to a building, 3 escalators up, 2 esclators down.
How many ways can a person enter from outside, go to the second floor, return to the first floor, then leave the building?

I believe you would do 4 x 3 x 12 = 24 ways. .??
I assume that the four entrances are used as exits.

The person has 4 choices of entrances,
. . then 3 choices of up-escalators,
. . then 2 choices of down-escalators,
. . then 4 choices of exits.

There are: .4 × 3 × 2 × 4 = 96 ways.

2) A six-sided die and a fair coin are tossed together.
How many outcomes are in the sample space?
I believe its 8 outcomes.
No, we don't add them.

The die has 6 possible outcomes: 1, 2, 3, 4, 5, 6.
The coin has 2 possible outcomes: Heads or Tails.

Look at what could happen:
. . (1,H), (2,H), (3,H), (4,H), (5,H), (6,H)
. . (1,T), (2,T), (3,T), (4,T), (5,T), (6,T)

There are 12 outcomes.
. . (That's right: we <u>multiply</u> them.)
 
Thank you very much


soroban said:
Hello, Ryan!

1)There are 4 entrances to a building, 3 escalators up, 2 esclators down.
How many ways can a person enter from outside, go to the second floor, return to the first floor, then leave the building?

I believe you would do 4 x 3 x 12 = 24 ways. .??
I assume that the four entrances are used as exits.

The person has 4 choices of entrances,
. . then 3 choices of up-escalators,
. . then 2 choices of down-escalators,
. . then 4 choices of exits.

There are: .4 × 3 × 2 × 4 = 96 ways.

[quote:1pju0cx5]2) A six-sided die and a fair coin are tossed together.
How many outcomes are in the sample space?
I believe its 8 outcomes.
No, we don't add them.

The die has 6 possible outcomes: 1, 2, 3, 4, 5, 6.
The coin has 2 possible outcomes: Heads or Tails.

Look at what could happen:
. . (1,H), (2,H), (3,H), (4,H), (5,H), (6,H)
. . (1,T), (2,T), (3,T), (4,T), (5,T), (6,T)

There are 12 outcomes.
. . (That's right: we <u>multiply</u> them.)[/quote:1pju0cx5]
 
May I also have help with one more question:

Ellen had 4 pairs of slacks, 3 shirts, and 3 scarves that all match. How many outfits that include slacks, a shirt, and a scarf can she put together?
Construct a tree diagram to answer the question.

Thanks in advance,
Ryan
 
rgeer said:
May I also have help with one more question:
Ellen had 4 pairs of slacks, 3 shirts, and 3 scarves that all match. How many outfits that include slacks, a shirt, and a scarf can she put together?
Construct a tree diagram to answer the question.
Thanks in advance,
Ryan
You don't seem to have learned anything from soroban's work, Ryan;
are you tired or something?

x=slacks, y=shirts, z=scarves

x1, y1, z1:z2:z3
...
x4, y3, z1:z2:z3

Now get busy and figure out what's in between.
 
Im still not sure how to construct the tree diagram,

I believe what Denis is saying is that:

on the left you would put

x branched: y-123-branched z-123
x
x
x

Then the same thing for all of them following.

I think thats how you do it. Can someone please verify this.

Thanks in advance,
Ryan
 
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