im completly lost

megan1710

New member
Joined
Jan 18, 2006
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3
so basically im wayy behind in algebra! like a couple of chapters! so its all very fusteratingg! but how do you write a point-slope form equation when slope is -4 (-3, 1) and how did you get your answerr! thank youu
 
I don't quite understand your post. What does -4(-3, 1) mean?. Maybe (12, -4)?.

Anyway, point-slope form is \(\displaystyle y-y_{1}=m(x-x_{1})\), where m is the slope.

\(\displaystyle m=\frac{y-y_{1}}{x-x_{1}}\)
 
galactus said:
I don't quite understand your post. What does -4(-3, 1) mean?. Maybe (12, -4)?.

Anyway, point-slope form is \(\displaystyle y-y_{1}=m(x-x_{1})\), where m is the slope.

\(\displaystyle m=\frac{y-y_{1}}{x-x_{1}}\)
the problem says - write an equation in point slope form for the line that has given slope and the contains the given point, and then change the equation to slope-intercept form

sleope -4 (2, 6)
 
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