[(x^2 + 8x + 12)/(x^2 + 4x - 12)]/[(x^2 + 6x + 8)/(x^2 + 3x - 10)] = (x + 5)/(x + 4) MANDY
G Guest Guest Jan 26, 2006 #1 [(x^2 + 8x + 12)/(x^2 + 4x - 12)]/[(x^2 + 6x + 8)/(x^2 + 3x - 10)] = (x + 5)/(x + 4) MANDY
U Unco Senior Member Joined Jul 21, 2005 Messages 1,134 Jan 26, 2006 #2 Factor each quadratic and observe some cancellation.
U Unco Senior Member Joined Jul 21, 2005 Messages 1,134 Jan 26, 2006 #4 Actually if you were just checking, your first answer is perfectly correct; nice work.