formula

maggie0160

New member
Joined
Oct 19, 2005
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22
Can someone help me with this?

Find f'(x) when x has the given value.

f(x) = square root of x ; x = 121

What is the formula I can't find how to do this in my book. I have been stuck on it for 4 days now.
 
\(\displaystyle \L \mbox{ f(x) = \sqrt{x} = x^{\frac{1}{2}}}\)

Now can you differentiate to find f'(x)?
 
No; f(121) = 11, but f'(121) does not.

Since you posted this question to one of the "algebra" categories, rather than to the "calculus" category, I would wonder what sort of technique, method, or formula you are supposed to use to find the first derivative (which is something you will learn about once you reach calculus).

Please let us know how you're supposed to approach this exercise. Thank you.

Eliz.
 
Hello Maggie,

I am less experienced so you may want to have a tutor double check but i did this and got 2 different answers. First I got 1/11 and the second time I got 121.
 
TinyTim said:
I am less experienced so you may want to have a tutor double check but i did this and got 2 different answers. First I got 1/11 and the second time I got 121.
I'm sorry, but neither of these is correct.

Eliz.
 
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