digit and coin word problems

Straight edge man

New member
Joined
Jan 31, 2006
Messages
16
ok well my teacher told us there are two equations we will need for all of the problems... well i dont have them and i dont know how to get them... well here is problem number one, the one he gave us the equations on.... (also i dont know how to do this)...
The sum of the digits of a two-digit number is 9. If the digits are reversed, the new number if ( i think it meant is) 63 greater than the original number. Find the original number.

I would greatly appreciate it if you helped me.
Thank you
 
The first number is 10a+b
The second number is 10b+a
10a+b+63=10b+a
a+b=9
Two equations in two unknowns.
 
a+b=9 and the original number is 10a+b, remember?
---------------
Gene
 
Top