3 3 a - b I do not remember how to factor this out. [/code][/quote][/u][/i][/b]
J jenrand New member Joined Feb 4, 2006 Messages 1 Feb 4, 2006 #1 3 3 a - b I do not remember how to factor this out. [/code][/quote][/u][/i][/b]
H happy Full Member Joined Oct 30, 2004 Messages 466 Feb 4, 2006 #2 No wonder, your problem makes no sense.
M Matt Junior Member Joined Jul 3, 2005 Messages 183 Feb 4, 2006 #3 Hi Jenrand, jenrand said: \(\displaystyle \L a^3-b^3\) I do not remember how to factor this out. Click to expand... The formula is: \(\displaystyle \L a^3-b^3=(a-b)(a^2+ab+b^2).\)
Hi Jenrand, jenrand said: \(\displaystyle \L a^3-b^3\) I do not remember how to factor this out. Click to expand... The formula is: \(\displaystyle \L a^3-b^3=(a-b)(a^2+ab+b^2).\)
M Matt Junior Member Joined Jul 3, 2005 Messages 183 Feb 4, 2006 #4 A useful mnemonic for the sum or difference of two cubes is SOAP, an acronym for: Same Opposite Always Positive
A useful mnemonic for the sum or difference of two cubes is SOAP, an acronym for: Same Opposite Always Positive
M Mrspi Senior Member Joined Dec 17, 2005 Messages 2,128 Feb 4, 2006 #5 jenrand said: 3 3 a - b Matt has given you a great response. Please make sure that you have MEMORIZED these patterns: a<SUP>3</SUP> + b<SUP>3</SUP> = (a + b)(a<SUP>2</SUP> - ab + b<SUP>2</SUP>) a<SUP>3</SUP> - b<SUP>3</SUP> = (a - b)(a<SUP>2</SUP> + ab + b<SUP>2</SUP>) Click to expand...
jenrand said: 3 3 a - b Matt has given you a great response. Please make sure that you have MEMORIZED these patterns: a<SUP>3</SUP> + b<SUP>3</SUP> = (a + b)(a<SUP>2</SUP> - ab + b<SUP>2</SUP>) a<SUP>3</SUP> - b<SUP>3</SUP> = (a - b)(a<SUP>2</SUP> + ab + b<SUP>2</SUP>) Click to expand...
