With "1" being "100% of the regular size", what will the size be after one enlargement? Then apply the same multiplication to this result to get the size after a second enlargement. Compare the result with "1" to find the total final enlargement.Flower9 said:1.A duplicating machine enlarges a picture 30%. If that enlarger is used 2 times, about how many times as large as the original picture will the final picture be?
Does this actually mean "(x^13)/(x^6)" (that is, "x<sup>13</sup>/x<sup>6</sup>")? If so, just expand, cancel off the common factors, and collapse the result back into exponential notation. For instance:Flower9 said:2.Simplify x13/x6
Flower9 said:1.A duplicating machine enlarges a picture 30%. If that enlarger is used 2 times, about how many times as large as the original picture will the final picture be?
If you mean 2 more times: (1.3)^3
2.Simplify
x13/x6
If x^13 / x^6: hint: 1 / a^b = a^(-b)
Next time SHOW your work...