A couple of quick ones?

Flower9

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Feb 5, 2006
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1.A duplicating machine enlarges a picture 30%. If that enlarger is used 2 times, about how many times as large as the original picture will the final picture be?


2.Simplify

x13/x6

Thank you!
 
Flower9 said:
1.A duplicating machine enlarges a picture 30%. If that enlarger is used 2 times, about how many times as large as the original picture will the final picture be?
With "1" being "100% of the regular size", what will the size be after one enlargement? Then apply the same multiplication to this result to get the size after a second enlargement. Compare the result with "1" to find the total final enlargement.

Flower9 said:
2.Simplify x13/x6
Does this actually mean "(x^13)/(x^6)" (that is, "x<sup>13</sup>/x<sup>6</sup>")? If so, just expand, cancel off the common factors, and collapse the result back into exponential notation. For instance:

. . . . .m<sup>5</sup>/m<sup>7</sup> = [mmmmm] / [mmmmmmm] = 1/[mm] = 1/m<sup>2</sup>

Eliz.
 
Flower9 said:
1.A duplicating machine enlarges a picture 30%. If that enlarger is used 2 times, about how many times as large as the original picture will the final picture be?

If you mean 2 more times: (1.3)^3

2.Simplify
x13/x6

If x^13 / x^6: hint: 1 / a^b = a^(-b)

Next time SHOW your work...
 
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