GOD HELP ME elimination =,- and multi
- Thread starter chris666
- Start date
I assume you meant to write:
eq1. 3m-4n=-14
eq2. 3m-2n=-2
This is a system of equations, which means that m and n have the same values in both equations. To eliminate one of the variables, you can solve eq1 for either m or n, and then plug that value into eq2.
You can also solve with with the addition/subtraction method. I suggest you read your book if you are confused by this.
eq1. 3m-4n=-14
eq2. 3m-2n=-2
This is a system of equations, which means that m and n have the same values in both equations. To eliminate one of the variables, you can solve eq1 for either m or n, and then plug that value into eq2.
You can also solve with with the addition/subtraction method. I suggest you read your book if you are confused by this.
G
Guest
Guest
Here is your answer.
I can't believe I can actually help someone with algebra! This is what you need to do.
3m - 4n = -14
First you need to put a + sign in front of the -4n.
3m + -4n = -14
Next you need to figure out what m and n stand for. They are hidden numbers. The signs are very important. -2 and 2 are your hidden numbers. So what you are going to do is substitute those numbers in for the letters, like this.
(3-2) + (-42) = -14
Now remember you are multiplying the numbers in the parenthesis.
(3-2) + -42) = -14
-6 + -8 = -14
The most important thing is figuring out which hidden numbers times the numbers you currently have will equal your answer and using the correct signs. Hope this helps.
I can't believe I can actually help someone with algebra! This is what you need to do.
3m - 4n = -14
First you need to put a + sign in front of the -4n.
3m + -4n = -14
Next you need to figure out what m and n stand for. They are hidden numbers. The signs are very important. -2 and 2 are your hidden numbers. So what you are going to do is substitute those numbers in for the letters, like this.
(3-2) + (-42) = -14
Now remember you are multiplying the numbers in the parenthesis.
(3-2) + -42) = -14
-6 + -8 = -14
The most important thing is figuring out which hidden numbers times the numbers you currently have will equal your answer and using the correct signs. Hope this helps.
Nooooo, Christina; there are 2 equations; other one is:
3m-2n=-2
3(-2) - 2(2) = -6 - 4 = -10; that's not -2
You need to find a solution that fits BOTH equations.
See daon's post.
Here's a way to do it:
I'll let you calculate m
3m-2n=-2
3(-2) - 2(2) = -6 - 4 = -10; that's not -2
You need to find a solution that fits BOTH equations.
See daon's post.
Here's a way to do it:
Code:
-3m + 4n = 14 : eq 1 multiplied by -1
3m - 2n = -2 : eq 2
Add them together:
2n = 12
n = 12/2 = 6
G
Guest
Guest
Denis said:
I didn't know there were 2 equations.
The answer to the second equation would be -2 and -2 if it were by itself.artistic_c said:3m - 2n = -2 : eq 2
I didn't know there were 2 equations.
True, BUT there are other solutions:
m=-4 and n=-5
m=0 and n=1
m=2 and n=4
m=4 and n=7
and many more...to infinity!
REMEMBER: when there are TWO unknowns, you need TWO equations.