boscothepug1 said:
Solve -8d-5 less than or greater to 2d-3
Is this is "less than" inequality, or a "greater than" one? (You've got both in the same statement.)
If I understand you correctly (and using an "equals" sign to stand in for the unknown inequality sign, for the time being), you have done the following:
. . . . .\(\displaystyle \large{-8d\,-\,5\,=\,2d\,-\,3}\)
. . . . .\(\displaystyle \large{-8d\,-\,5\,+\,5\,=\,2d\,-\,3\,+\,5}\)
. . . . .\(\displaystyle \large{-8d\,=\,2d\,+\,2}\)
. . . . .\(\displaystyle \large{\frac{-8d}{-8d}\,=\,\frac{2d\,+\,2}{-8d}}\)
. . . . .\(\displaystyle \large{1\,=\,\frac{2d}{-8d}\,+\,\frac{2}{-8d}}\)
. . . . .\(\displaystyle \large{1\,=\,-\frac{1}{4}\,-\,\frac{1}{4d}}\)
Is this a correct interpretation of what you have done thus far?
Thank you.
Eliz.