is this right?? [2^(x+1)][2^(1-x)] / 2^x 2^(4-x) = 2^2 / 2^4 = 4/16 =1/4
T Tascja New member Joined Mar 4, 2006 Messages 46 Mar 4, 2006 #1 is this right?? [2^(x+1)][2^(1-x)] / 2^x 2^(4-x) = 2^2 / 2^4 = 4/16 =1/4
skeeter Elite Member Joined Dec 15, 2005 Messages 3,215 Mar 4, 2006 #2 bingo! good job. also ... notice that 2^2/2^4 = 2^(-2) = 1/(2^2) = 1/4
T Tascja New member Joined Mar 4, 2006 Messages 46 Mar 4, 2006 #3 ok could u help me with this one too? is this right?? [ (a^2 b)^n / c^3n X (ac^n)^3 / b^3 ] = [ (a^2n b^n) / c^3n X (a^3 c^3n) / b^3 ] = [ (a^5n b^n c^3n) / c^3n b^3 ] = [ (a^5n b^n ) / b^3 ]
ok could u help me with this one too? is this right?? [ (a^2 b)^n / c^3n X (ac^n)^3 / b^3 ] = [ (a^2n b^n) / c^3n X (a^3 c^3n) / b^3 ] = [ (a^5n b^n c^3n) / c^3n b^3 ] = [ (a^5n b^n ) / b^3 ]
skeeter Elite Member Joined Dec 15, 2005 Messages 3,215 Mar 4, 2006 #4 (a^2* b)^n / c^(3n) X (a*c^n)^3 / b^3 = [a^(2n)*b^n] / c^(3n) X [a^3*c^(3n)] / b^3 = [a^(2n+3)*b^n*c^(3n)] / [c^(3n)*b^3] = [a^(2n+3)*b^n] / b^3 = a^(2n+3)*b^(n-3)
(a^2* b)^n / c^(3n) X (a*c^n)^3 / b^3 = [a^(2n)*b^n] / c^(3n) X [a^3*c^(3n)] / b^3 = [a^(2n+3)*b^n*c^(3n)] / [c^(3n)*b^3] = [a^(2n+3)*b^n] / b^3 = a^(2n+3)*b^(n-3)
G Gene Senior Member Joined Oct 8, 2003 Messages 1,904 Mar 4, 2006 #5 Don't use x for times. It is often impossible to tell if it is times or the variable x. Use * for times. ---------------- Gene
Don't use x for times. It is often impossible to tell if it is times or the variable x. Use * for times. ---------------- Gene
