help me please

[Guest]

How do you do a factor completely right?
The question is y(y-5)-7(y-5) i thought you would first find the common numbers like the two 5 and then the 7 which would = ((y+5)(y-7) Is this right?
I am getting confused on the postive and negative numbers all the time. What is the best solution for this?

 

[Gene]

First get rid of the ()s by distributing the y & 7, then gather like terms (you get a quadratic) and factor the result.
Or
You have a common term (y-5). Factor that out to get (y-5) times (?-?)

 

[Mrspi]

How do you do a factor completely right?
The question is y(y-5)-7(y-5) i thought you would first find the common numbers like the two 5 and then the 7 which would = ((y+5)(y-7) Is this right?
I am getting confused on the postive and negative numbers all the time. What is the best solution for this?

Do you see that each term has a factor of (y - 5)?

y(y -5) - 7(y - 5)

Remove that common factor, and put what is left from each term inside a second set of parentheses:

(y - 5)(y - 7)

Note that after you remove the (y - 5), "y" is left from the first term, and -7 is left from the second term.

I hope this helps you.

 

[mowlick]

y(y-5)-7(y-5) =

(y^2 -5y) - (7y -35) =

y^2 -5y - 7y - -3 5 =

y^2 -5y - 7y + 35 =

y^2 -12y + 35 =

(y - 5)(y - 7)