Absolute Value Question

[Guest]

this might be kinda simple but here it goes

3x > |2-3x| Solve for x

Part 1:

Let 2-3x >= 0
Only valid when x <= 2/3

3x > 2-3x
x > 1/3

Part 2:

Let 2-3x < 0
Only valid when x > 2/3

3x > 3x-2
0 > -2

I got up to here and became confused. In part 2 should x=all real numbers? What should my solution be?

 

[wjm11]

3x > |2-3x| Solve for x

As you stated, x> 1/3 is your solution.