Eliz and pka... thank you both very much. (I'm getting it. I'm gone.) John
Eliz and pka... thank you both very much. (I'm getting it. I'm gone.) John
A struggling student.
Sooooooo:
show "radicand of n" this way : sqrt(n)
3x^2 = 3 times x^2
(3x)^2 = 9 times x^2
Mais oui, Jean ?
I'm just an imagination of your figment !
pka,
I did well with your first 2 examples, but the third:
(-xy^2)^4*(x^3y^2)^3 = (x^4y^8)(x^9y^6) = x^13y^14
is a puzzle (to me). The first parenthetical term: (-xy^2)^4
Isn't there an invisible "1" between the minus sign and the "x"? Raising "-1x" to the 4th power looks like (-1x)(-1x)(-1x)(-1x). Does this not require the "Same Sign Rule"... to keep the sign and add the numbers? Result would be (-x^4y^8)
Did you intentionally throw me a curve, or am I still thick?
John
PS A belated thank you, Denis.
A struggling student.
What is (-1)<sup>4</sup>?
Eliz.
Eliz,
Thank you. 1 to the 4th power would be 1. The term is (-1x)^4. What happens to the minus sign?
John
A struggling student.
Originally Posted by John Whitaker
Mr. Whitaker, you must learn the basic idea.
[tex]\left( {ab} \right)^n = a^n b^n[/tex] this is true period!
[tex]\left( { - x} \right)^4 = \left( { - 1x} \right)^4 = \left( { - 1} \right)^4 \left( x \right)^4 = x^4[/tex]
For any even counting number n , [tex]\left( { - x} \right)^n = x^n[/tex].
Why? Because n is even, n=2j for some j, so
[tex]\left( { - x} \right)^n = \left( { - x} \right)^{2j} = \left[ {\left( { - x} \right)^2 } \right]^j = \left( {x^2 } \right)^j = x^{2j} = x^n[/tex]
Now What happens to the minus sign?
“A professor is someone who talks in someone else’s sleep”
W.H. Auden
Yes, but that doesn't answer my question.
You are correct that (1)<sup>4</sup> = 1. But what is (-1)<sup>4</sup>?
Eliz.
Eliz,
(-1)^4... That would be "-1"
If you can see the 3 samples pka gave me, look at the first parenthetical term in the second sample... and the same in the third.
RE: The second: (-xy^2)^4 If the simplication of that is -x^3y^6, then the simplication of sample #3: (-xy^2)4 should be (-x^4y^8). pka shows it to be: (x^4y^8). This is what I question. What happened to the minus sign in pka's third sample?
John
A struggling student.
I give up!
The dragon of confusion has slain George the reasonable!
“A professor is someone who talks in someone else’s sleep”
W.H. Auden
You're not alone. I have no either what John is doing or trying to convey to us either.I give up!
The dragon of confusion has slain George the reasonable!
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