christie_11
New member
- Joined
- Oct 11, 2006
- Messages
- 2
Collision impact of an automobile varies jointly as its mass and the square of its speed. Suppose a 2000lb car was traveling 55mph has a collision impact of 6.1. What is the collison impact of the same car at 65mph?
I realize that its a joint variation, for which the equation is "y = kxz", right? I'm setting up the problem:
. . .2000 = 55(6.1)
. . .2000 = 335.5
Then I divide by 335.5 and get k = 5.9
I do not understand how to get the second part, y = 5.9xz, because I get a really large number.
I realize that its a joint variation, for which the equation is "y = kxz", right? I'm setting up the problem:
. . .2000 = 55(6.1)
. . .2000 = 335.5
Then I divide by 335.5 and get k = 5.9
I do not understand how to get the second part, y = 5.9xz, because I get a really large number.