Combining like terms and Compound Inequalities...I need help

italianblonde518

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Oct 25, 2006
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Can anyone help me with these 2 math problems?

Number 1. Solve agebraically for x:


8 (1/2x + 6) - 2( x - 1 ) = 1/3 (6x - 9)



Number 2: Compound Inequalities:

2 (x - 1) - x <_ -8 ( x - 2) + 1

*** <_ is my way of writing less than or equal to.
 
For number 1:

8 [ 1/2x + 6 ] - 2[ x - 1 ] = 1/3 [ 6x -9 ]

First you would multiply 8 times 1/2x and 8 times 6.

Now having,

4x + 48.

Then you would multiply -2 times both x and -1 to get,

4x + 48 - 2x + 2

Next, you multiply 1/3 times 6x and -9 to get,

4x + 48 - 2x + 2 = 2x - 3

Then you combine the like terms 4x - 2x,

and also combine 48 + 2.

You now have the inequality:

2x + 50 = 2x - 3

Next you subtract 2x from each side,

giving you 50 = x - 3.

Last, you add 3 to each side.

Your final inequality:

53 = x or x = 53


There you go.
 
That was what I got when I tried to solve this equation was 53, however, when I went to check my answer by computing the solution into the original problem, the numbers did not add up???? :oops:
 
BR2010 said:
You now have the inequality: 2x + 50 = 2x - 3
Since this has an "equals" sign, not an inequality symbol, this is actually an equation, not an inequality.

BR2010 said:
Next you subtract 2x from each side, giving you 50 = x - 3
Actually, since 2x - 2x = 0, not x, one should get "50 = -3", or "no solution".

italianblonde518 said:
That was what I got....
This is why it is requested that posters show their work. Without knowing your steps, we cannot help you find your error.

I have corrected the first exercise for you. Please reply showing your work for the second exercise. Thank you.

Eliz.
 
BR2010 said:
2x + 50 = 2x - 3
Next you subtract 2x from each side,
giving you 50 = x - 3.
That's incorrect, BRrrrrrr
Subtracting 2x from each sides leaves: 50 = -3
So there is NO solution.

Did you post that equation PROPERLY, Blondie?
 
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