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Thread: Solving Multi-Step Equations: 21 = 6 - x - 4x

  1. #1

    Solving Multi-Step Equations: 21 = 6 - x - 4x

    I have a question, here is the problem 21=6-x-4x. And then I need to know how to check the answer. I would like you to reply as soon as possible please. I thank you for your help to. And when you reply could you tell me how long it regularly takes to reply.

  2. #2
    Full Member
    Join Date
    Jun 2006
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    553
    Hello, math87690!

    So many variable I can't tell you how long it take to reply.

    You can check your answer by filling what you found [tex]x[/tex] to be and see if the equation is balanced (same number on both side of the equations).

    So with that being said:

    [tex]\L \;21\,=\,6\,-x\,-4x[/tex]


    Combine like terms: [tex]\L \;21\,=\,6\,-5x[/tex]


    Subtract 6: [tex]\L \;15\,=\,-5x[/tex]


    Divide by -5: [tex]\L \;-3\,=\,x[/tex]


    ...........Transitive Property: [tex]\L \;x\,=\,-3[/tex]

    Now you fill [tex]x[/tex] back in our original equation ([tex]21\,=\,6\,-x\,-4x[/tex]) and see if it is balanced.
    Try your best in everything and don't be scared to do something different.

  3. #3
    Elite Member
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    Re: Solving Multi-Step Equations: 21 = 6 - x - 4x

    Quote Originally Posted by math87690
    I have a question, here is the problem 21=6-x-4x.
    Keep it simple
    Add 5x to both sides:
    5x + 21 = 6
    Subtract 21 from each sides:
    5x = -15
    Divide each side by 5:
    x = -3
    I'm just an imagination of your figment !

  4. #4
    Junior Member
    Join Date
    Nov 2006
    Posts
    85

    here's the proof it worked

    here's the proof it worked: I assigned -3 for x then plugged in the right hand side of the equation which, with x equivalent to -3, should equal 21 (the left side of the equation)

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