I am reviewing a test that I took. I got part of the answer correct and I am trying to understand how to do the second part correctly.
Solve: 27x^3 - 125 = 0
I started by factoring:
(3x - 5)(9x^2 + 15x + 25) = 0
3x - 5 = 0
3x = 5
x = 5/3
I am stuck with the second half of the equation as to where to start.
Solve: 27x^3 - 125 = 0
I started by factoring:
(3x - 5)(9x^2 + 15x + 25) = 0
3x - 5 = 0
3x = 5
x = 5/3
I am stuck with the second half of the equation as to where to start.