ultrasonicsite
New member
- Joined
- Dec 6, 2006
- Messages
- 11
What we're doing is Factoring by Grouping.
Example, third question on my sheet.
2x^2+x-6
The steps to solving that are:
1. Multiply the first and last terms, and place the products above the original quadratic.
2. Find factors of this product that add up to the original quadratic.
3. Group the first two and last terms together, and continue factoring.
Er, alright so basically doing that question:
2x^2+x-6
We, or I, multiply the beginning and the end.
(2x^2)(-6) = -12x^2
Now we find the factor(s) of -12
-1 and 12
1 and -12
-2 and 6
2 and -6
-3 and 4
3 and -4
Which one of these factors equals x
ax^2+bx+c is the "Factoring Pattern)
Well, either I'm stuck here, or the answer is "Prime"
-Heh, what are your thoughts on it?
Example, third question on my sheet.
2x^2+x-6
The steps to solving that are:
1. Multiply the first and last terms, and place the products above the original quadratic.
2. Find factors of this product that add up to the original quadratic.
3. Group the first two and last terms together, and continue factoring.
Er, alright so basically doing that question:
2x^2+x-6
We, or I, multiply the beginning and the end.
(2x^2)(-6) = -12x^2
Now we find the factor(s) of -12
-1 and 12
1 and -12
-2 and 6
2 and -6
-3 and 4
3 and -4
Which one of these factors equals x
ax^2+bx+c is the "Factoring Pattern)
Well, either I'm stuck here, or the answer is "Prime"
-Heh, what are your thoughts on it?