An isosceles right triangle is inscribed in a circle. If....

[dwill]

An isosceles right triangle is inscribed in a circle. If the area of the circle is 16 pi, what is the area of the triangle?

A= pi r2
16 pi =pi r2

16 = r2
4 = r
8 = diameter
Area of Triangle
A = ½ bh

Diameter of circle --> hypotenuse of triangle
Triangle 4 by 4 sqrt 3 by 8

A = ½ (4 * 4 sqrt 3)

A= 4 sqrt 3
????

Is this correct
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[pka]

Have you forgotten that this is isosceles right triangle ?

 

[dwill]

ok, so the sides are 4 and 4 sqrt 3 and the hyp is 8 correct?
I guess I am having problems with solving for area.
A= 1/2 bh

I am not sure how to solve, would you able to show me the math?

 

[pka]

NO!
What does "isosceles right triangle" mean?

 

[dwill]

NO!
What does "isosceles right triangle" mean?

Thank you, I knew I was overlooking something but I was not sure what.
But there is really no need to yell, I am on this website because I need help.
If I knew correct steps to the solution... I would not post. .

But thanks again.

 

[pka]

Who yelled?
Have you considered that it simply got you attention?
Didn’t that help you? Isn’t that the point?

 

[Denis]

dwill, draw a square, then a circle going through the 4 corner points
of the square....see the light? :wink: