Simplify secX+cscX/1+tanX

adpcane15 said:
Simplify secX+cscX/1+tanX
Does the above mean either of the following?

. . . . .sec(x) + [ csc(x) / (1 + tan(x)) ]

. . . . .[ sec(x) + csc(x) ] / [ 1 + tan(x) ]

Or something else?

What have you tried so far?

Please be specific. Thank you.

Eliz.
 
Hello, adpcane15!

Simplify: \(\displaystyle \L\:\frac{\sec x\,+\,\csc x}{1\,+\,\tan x}\)

Convert to sines and cosines: \(\displaystyle \L\:\frac{\frac{1}{\cos x}\,+\,\frac{1}{\sin x}}{1\,+\,\frac{\sin x}{\cos x}}\)


Multply top and bottom by \(\displaystyle \sin x\cdot\cos x\)

. . \(\displaystyle \L\frac{\sin x\cdot\cos x}{\sin x\cdot\cos x}\,\cdot\,\frac{\frac{1}{\cos x}\,+\,\frac{1}{\sin x}}{1\,+\,\frac{\sin x}{\cos x}} \;=\;\frac{\sin x\,+\,\cos x}{\sin x\cdot\cos x\,+\,\sin^2x}\)

Factor and reduce: \(\displaystyle \L\:\frac{\sout{\sin x\,+\,\cos x}}{\sin x(\sout{\cos x\,+\,\sin x})} \;=\;\frac{1}{\sin x} \;=\;\csc x\)

 
stapel said:
What have you tried so far? Please be specific. Thank you.
Well, never mind that now.... :?

Eliz.
 
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