The acceleration of a vehicle takes the form du/dt =3.6 - 0.06u where u is the vehicle speed in ft/sec. The vehicle is traveling at 45 ft/sec at time T.
a) Determine the distance traveled by the vehicle when accelerated to a speed of 55 ft/sec.
b) Determine the time at which the vehicle attains the speed of 55 ft/sec.
c) Determine the acceleration of the vehicle after 3 sec.
I solved the problem and just wanted someone to confirm that it's correct. For a) i got x= 81.47 ft and for b) i got t=1.78sec and c) a =0.85 ft/s.
I used the 3 equations that were given in the book:
x=1/2at^2+Vt
u= (alpha/beta)(1-e^(-beta*t)) + u_oe^(-beta*t)
x= (alpha/beta)t - (alpha/beta^2) (1-e^(-beta*t) + (u_o/beta)(1-e^(-beta*t))
du/dt= alpha - beta*u
Can someone please tell me if I did this correctly. Thanks!!!!!!
a) Determine the distance traveled by the vehicle when accelerated to a speed of 55 ft/sec.
b) Determine the time at which the vehicle attains the speed of 55 ft/sec.
c) Determine the acceleration of the vehicle after 3 sec.
I solved the problem and just wanted someone to confirm that it's correct. For a) i got x= 81.47 ft and for b) i got t=1.78sec and c) a =0.85 ft/s.
I used the 3 equations that were given in the book:
x=1/2at^2+Vt
u= (alpha/beta)(1-e^(-beta*t)) + u_oe^(-beta*t)
x= (alpha/beta)t - (alpha/beta^2) (1-e^(-beta*t) + (u_o/beta)(1-e^(-beta*t))
du/dt= alpha - beta*u
Can someone please tell me if I did this correctly. Thanks!!!!!!