# Thread: length 4 times width; find perim if area is 144; find 2 cons

1. ## length 4 times width; find perim if area is 144; find 2 cons

Ok guys I am really rusty now- Its been over 10 years I haven't done math really need the hlep.

Question 1: The length of a rectangl is 4 times its width. If the area is 144cm2 (thats square), find its perimeter?

Question 2: Find 2 consective odd intergers whose sum is 56.?

2. ## Re: Problems

25 posts and you have not learned that the most effective post is the post that SHOWS WORK. You have only typed the problem statements. Please do better than that.

For the rectangle, you need only

1) Length * Width = Area
2) 2*Length + 2*Width = Perimeter.

Draw a picture and look at it. You should see it.

For the odd integers, you need only a name for the odd integers. Write down a definition and show us what you get.

3. ## Re: Problems

Originally Posted by tkhunny
25 posts and you have not learned that the most effective post is the post that SHOWS WORK. You have only typed the problem statements. Please do better than that.

For the rectangle, you need only

1) Length * Width = Area
2) 2*Length + 2*Width = Perimeter.

Draw a picture and look at it. You should see it.

For the odd integers, you need only a name for the odd integers. Write down a definition and show us what you get.

the 2 odd intergers are 53 and 3. Is this correct?

I am still working on the perimeter

4. ## Re: Problems

The perimeter is 72. Is that correct?

5. ## Re: Problems

53 and 3 are not consecutive odd integers.

as far as the perimeter, let's see how you arrived at the value 72.

6. ## Re: Problems

Originally Posted by taragbeh
the 2 odd intergers are 53 and 3. Is this correct?
NO. They have to be CONSECUTIVE.

7. ## Re: Problems

Originally Posted by taragbeh
The perimeter is 72. Is that correct?
NO. Hint: w(4w) = 144

8. ## Re: Problems

Originally Posted by Denis
Originally Posted by taragbeh
The perimeter is 72. Is that correct?
NO. Hint: w(4w) = 144
Ok the perimetre is 36

9. ## Re: Problems

no, the perimeter is not 36, w[sup:wme6ykz7]2[/sup:wme6ykz7] is 36.

are you going to continue this guessing game?

10. ## Re: Problems

Originally Posted by skeeter
no, the perimeter is not 36, w[sup:11oqw26l]2[/sup:11oqw26l] is 36.

are you going to continue this guessing game?

I am trying to figure it out but not sue what i am doing but i am really trying.
ok so if

p=2l + 36

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