kaymarie said:b=2/3a
the fraction is confusing me, i'm not sure how to get started on it.
kaymarie said:... And then there's this problem:
b=(2/3)a grouping symbols added for clarity
the fraction is confusing me ...
Loren said:2x+5y=-2
y=-x/2
Replace the y in the first equation with -x/2 from the second equation getting...
\(\displaystyle 2x+5(\frac{-x}{2})=-2\)
and go from there.
Loren said:Replace the y in the first equation with -x/2 from the second equation getting...
\(\displaystyle 2x+5(\frac{-x}{2})=-2\) and go from there.
kaymarie said:But i still have that fraction in there, do i multiply like 5/1 times -x/2?
That was a very rude response, it was an honest question, i wasnt trying to sound like a dumbass. Thanks for you're lovely attitude with that.Mrspi said:Did you READ the previous responses? I'm guessing you didn't, or you would not be asking the SAME question again.
I am thinking that you would LIKE multiply both sides of your original equation by 2, since that is the denominator of the fraction in the equation....
2* 2x + 2*5(-x/2) = 2(-2)
4x + (-5x) = -4
NOW can you take it from here?
If you'd like to engage "honestly" in this process, then, by all means, please show some evidence of at least having read the replies.kaymarie said:That was a very rude response, it was an honest question...