Method of Transformations - Trig - Sin

plur222

New member
Joined
Mar 1, 2009
Messages
17
Using the method of transformations, I have to graph the following function p(t), and label the amplitude & period.

p(t) = 25 sin [ (8?/3) t ] + 115


I'm assuming I use p(t) = A sin (?t + ?) + d

But I am thrown off with the (8?/3) part, do I need to use a unit circle chart and solve first for this value?

HELP!
 
The amplitude is 25.

The period can be obtained from \(\displaystyle \frac{2\pi}{\omega}\)

Where \(\displaystyle {\omega}=\frac{8\pi}{3}\)

Therefore, the period is \(\displaystyle \frac{2\pi}{\frac{8\pi}{3}}=\frac{3}{4}\)
 
So I leave the (8?/3) alone then?
And set the graph to points of ?/3, 2?/3, 3?/3, 4?/3, 5?/3, etc...
How does the (t) effect the (8?/3) ?
Usually there is an addition or subtraction that effect the shift on the x-axis ... does the fact that it's multiplication mean I consider [(8?/3)t] to be a distortion on the x-axis?

Could I rewrite it as: 25 sin 8?/3(t) + 115

Where:
25 is the Distortion of Y
sin is the base
8?/3 is the Distortion of X
115 is the Shift of Y
 
This is what I have thus far ...?...
 

Attachments

  • Help.jpg
    Help.jpg
    19.2 KB · Views: 232
When you substitute in t = 0, you find that p(t) = 115, which is the resting pulse. If that is the upper number in the blood pressure reading, that is a fairly good number.
 
Top