Page 2 of 2 FirstFirst 12
Results 11 to 13 of 13

Thread: Two Identities

  1. #11

    Re: Two Identities

    hey guyx...i have a question...how i can solve this..

    (sinx cosx)/[(1+cosx)(1-cosx)]=cotx

  2. #12
    Senior Member
    Join Date
    Dec 2005
    Location
    CO, USA
    Posts
    2,082

    Re: Two Identities

    Quote Originally Posted by nisham209
    hey guyx...i have a question...how i can solve this..

    (sinx cosx)/[(1+cosx)(1-cosx)]=cotx
    Next time you have a question, please don't "highjack" someone else's thread. Use the button that says "new post" to submit your question in your OWN thread.

    That said, I suggest that you multiply out the two binomials in the denominator on the left side....

    what is (1 + cos x)(1 - cos x)??

    Then, look at the fundamental identities to see if there's something you could use to replace that expression.

    Having done that, see if you can simplify the left side.

    Please show us what you've done....

  3. #13

    Re: Two Identities

    Hey guys how do u solve this: cos(theta)cot(theta)/1-sin(theta) -1=csc(theta)

Bookmarks

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •