A circle with its centre on the y-axis intersects the graph of y x = at the origin, O, and exactly two other distinct points, A and B. Prove that the ratio
of the area of triangle ABO to the area of the circle is always 1 : ?.
Since the circle has centre on the y-axis (say, has coordinates (0,b)), then its radius is equal to b (and b must be positive for there to be three points of intersection). So the circle has equation x^2+(y-b)^2=b^2 I do not understand the sentence in bold. Can you please explain?
of the area of triangle ABO to the area of the circle is always 1 : ?.
Since the circle has centre on the y-axis (say, has coordinates (0,b)), then its radius is equal to b (and b must be positive for there to be three points of intersection). So the circle has equation x^2+(y-b)^2=b^2 I do not understand the sentence in bold. Can you please explain?