So the question is: Decide if the function is differentiable at x=0.
f(x)=((x+abs(x))^2)+1
My first instinct is to find the derivative of f(x) and then plug in x=0. My only problem is HOW do you find the derivative of an absolute value?
Since I didn't know how to find the derivative (hopefully someone can tell me the rule for absolute values) I did however use the derivative calculator on this website and found it to be
But then if you plug in zero you get a 0/0 situation at x/abs(x). So would that mean it is not differentiable at x=0? Because my textbook says that it is.
Thanks for any help you can offer.
f(x)=((x+abs(x))^2)+1
My first instinct is to find the derivative of f(x) and then plug in x=0. My only problem is HOW do you find the derivative of an absolute value?
Since I didn't know how to find the derivative (hopefully someone can tell me the rule for absolute values) I did however use the derivative calculator on this website and found it to be
But then if you plug in zero you get a 0/0 situation at x/abs(x). So would that mean it is not differentiable at x=0? Because my textbook says that it is.
Thanks for any help you can offer.