Need the formula to solve this please

chenarat

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Oct 12, 2011
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Tom jogs to work in 48 minutes. Jim bikes to work in 18 minutes. Jim bikes 12mph faster than Tom jogs. They both work in the same place. What is the distance to work?
 
Tom covers the distance d in d/V = 48 minutes = .8 hr.

Jim bikes 12 mph faster than Tom jogs arriving in d/(V + 12) = 18 minutes = .3 hr.

Since they cover the same distance d, .8V = .3V + 3.6.

Therefore, .5V = 3.6 or V = 7.2 mph

Then, d = 7.2(.8) = 5.76 miles.
 
@TchrWill, thanks for the help. I was on the right track after all it seems.

Tom covers the distance d in d/V = 48 minutes = .8 hr.

Jim bikes 12 mph faster than Tom jogs arriving in d/(V + 12) = 18 minutes = .3 hr.

Since they cover the same distance d, .8V = .3V + 3.6.

Therefore, .5V = 3.6 or V = 7.2 mph

Then, d = 7.2(.8) = 5.76 miles.[/QUO
 
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