pre algebra

I find it

x=3;
y=1;

Not quite, Larry. :cool:

You found one solution to 2x + 6y = 12. There are infinite solutions.

This exercise asks where the line crosses the axes (the intercepts).

We find the x-intercept by letting y = 0.

We find the y-intercept by letting x = 0.
 
x and y intercepts

need to find thex and y intercepts the problem is 2x+6y=12

To find the x-intercept, let y = 0 and solve for x. Let's do just that....

2x + 6y = 12

2x + 6(0) = 12

2x + 0 = 12

2x = 12

x = 12/2

x = 6.

To find the y-intercept, let x = 0 and solve for y.

2x + 6y = 12

2(0) + 6y = 12

0 + 6y = 12

6y = 12

y = 12/6

y = 2

The x-intercept is 6, which can be written as the point (6,0).

The y-intercept is 2, which can be written as the point (0,2).

What does this all mean anyway?

It means that the graph of the given equation 2x + 6y = 12 crosses the x-axis at the point (6,0) and crosses the y-axis at the point (0,2).

Is this clear?


 
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