can you help?

[yfelix45]

Hello,

I want thank everyone for their help so far.

How do I express y= 1/5(32^x) - 4 in terms of an equivalent equation.
So far this is what i have done:

y = 1/5(32^x) - 4
= 5^1(32^x) - 4

Is this right or is there another way to express this?

Thnaks
yihan

 

[srmichael]

Hello,

I want thank everyone for their help so far.

How do I express y= 1/5(32^x) - 4 in terms of an equivalent equation.
So far this is what i have done:

y = 1/5(32^x) - 4
= 5^1(32^x) - 4

Is this right or is there another way to express this?

Thnaks
yihan

Original Equation: \(\displaystyle y=\frac{1}{5}(32^x)-4\)

There are many ways that one can rewrite this equation, but just going off of your solution, \(\displaystyle \frac{1}{5} = 5^{-1}\) so really what you would have is:

\(\displaystyle y=5^{-1}(32^x)-4\)

 

[Deleted member 4993]

Hello,

I want thank everyone for their help so far.

How do I express y= 1/5(32^x) - 4 in terms of an equivalent equation.
So far this is what i have done:

y = 1/5(32^x) - 4
= 5^1(32^x) - 4

Is this right or is there another way to express this?

Thnaks
yihan

I think the question to be answered is - what is the equivalent simple equation, which can be transformed to the given one?

\(\displaystyle y \ = \ \frac{1}{5}32^x \ - \ 4\)

The equation can be re-written as:

\(\displaystyle y \ = \ \frac{1}{5}2^{5x} \ - \ 4\)

Now the equivalent simple equation - which can be transformed to the given equation through translation, contraction and expansion - can be deduced.

 

[yfelix45]

thank you

Thanks,For all the help.It is greatly appreciated especially from soroban, denis and subhotosh khan



yfelix45