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Thread: show that the curvature of a circle of radius 'a' equals 1/a

  1. #1
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    show that the curvature of a circle of radius 'a' equals 1/a

    show that the curvature of a circle of radius 'a' equals 1/a
    plz help me if any body can solve it plz

  2. #2
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    Quote Originally Posted by waseemshahzada View Post
    show that the curvature of a circle of radius 'a' equals 1/a
    Let [TEX]r(t)=a\cos(t)+a\sin(t)[/TEX] be a circle of radius [TEX]a[/TEX].

    Then [TEX]\bf{T}(t)=\dfrac{r'(t)}{\|r'(t)\|}[/TEX].

    Then curvature is [TEX]\kappa(t)=\dfrac{\|\bf{T}'(t)\|}{\|r'(t)\|}[/TEX].

    Now you do the work.
    “A professor is someone who talks in someone else’s sleep”
    W.H. Auden

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