Here is the inequality

[TEX]\left( 1 - a \right) < 1[/TEX],

where [TEX] 0 < a < 1[/TEX]

Taking the base 2 antilogarithm of both sides gives

[TEX]2^{\left( 1 - a \right)} < 2[/TEX]

I am not sure if this is antilogarithm operation is allowed because the quanitity [TEX]\left( 1 - a \right)[/TEX] is less than one.

P.S. I am not trying to solve this for [TEX]a[/TEX]. I am just using this as an example so I can figure this out.

Thanks for your help!

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