I tried integrating this on my own but couldn't get the correct answer. I'm not supposed to use any reduction formulas. Any help is much appreciated
Integral (cos42x dx)
Integral (1/2(1-cos 4x))2
Integral ([1/4(1-2cos 4x- cos24x)][1/4(1-2cos 4x - cos 24x)]dx)
1/8 integral ((1-2cos4x - cos 24x)(1-2cos 4x - cos 24x) dx)
1/8 integral (1-2cos 4x - cos24x-2 cos 4x-4cos 24x - 2 cos 34x - cos24x - 2 cos34x - cos44x
1/8 integral (1-4cos4x-6cos24x - 4 cos34x -cos44x dx)
I stopped here because it wouldn't give me the answer I needed. The answer is
1/64 (24x + 8 sin 4x + 8 sin x) + C
Integral (cos42x dx)
Integral (1/2(1-cos 4x))2
Integral ([1/4(1-2cos 4x- cos24x)][1/4(1-2cos 4x - cos 24x)]dx)
1/8 integral ((1-2cos4x - cos 24x)(1-2cos 4x - cos 24x) dx)
1/8 integral (1-2cos 4x - cos24x-2 cos 4x-4cos 24x - 2 cos 34x - cos24x - 2 cos34x - cos44x
1/8 integral (1-4cos4x-6cos24x - 4 cos34x -cos44x dx)
I stopped here because it wouldn't give me the answer I needed. The answer is
1/64 (24x + 8 sin 4x + 8 sin x) + C