How to find and solve the equation of a circle with radius 5 radical 2 and center (-3,2)???
How to find and solve the equation of a circle with radius 5 radical 2 and center (-3,2)???
The general form for the equation of a circle with center (h, k) and radius r is
(x - h)^{2} + (y - k)^{2} = r^{2}
You are GIVEN the center: (-3, 2) so if (h, k) = (-3, 2) then h = -3 and k = 2.
You are GIVEN that the radius is 5 sqrt(2)...that's r.
The equation of the circle in standard form, then, is
(x - (-3))^{2} + (y - 2)^{2} = [5 sqrt(2)]^{2}
Can you do some simplification?
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He's right, I got the equation mixed up, the answer would be;
[TEX](X + 3)^2 + (Y - 2)^2 \:=\: 25[/TEX]
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