How do you take the geometric/taylor (unsure which it is) series of log(1-t)?
I do already have a result given to me of 0 -t -(t^2)/2 -(t^3)/3 -(t^4)/4 -...
But don't know where its come from?
Also, I need to find log(1-t)-log(1-2t) in that form but getting different answers with my friend so would like some reassurement!
is it just (-t -(t^2)/2 -(t^3)/3 -(t^4)/4 -...) - (-2t -((2t)^2)/2 -((2t)^3)/3 -((2t)^4)/4 -... ?