
New Member
Evaluate the Integral
Is this the correct answer?
Evaluate the following integrals
1
∫ ((2x)/(sqrt1+2x))dx
0
ITG = (2/3)*(x1)*sqrt(2x+1) + C
ITG(1) = 0
ITG(0) = 2/3
ITG(1)  ITG(0) = 2/3
> 2/3

Senior Member
No, it isn't. Unfortunately, since you did not show how you did the integral, I cannot say how to correct it. Did you make the sustitution u= 1+ 2x?

New Member
I attached a picture of my work below. Thank you for looking over this problem. Where did I go wrong?

Senior Member
When you make the substitution [tex]u= v^2[/tex], you have dv= 2udu but you have treated it as if it were du= 2vdv.
Instead, use the fact that [tex]\frac{u1}{\sqrt{u}}= u^{1/2} u^{1/2}[/tex].
Posting Permissions
 You may not post new threads
 You may not post replies
 You may not post attachments
 You may not edit your posts

Forum Rules
Bookmarks