1-100 using four nines

david3456777

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Joined
May 15, 2012
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6
hey my goal in school is to get to 1-100 only using four nines and it's due TOMMOROW somebody help me get to there and do it fast PLEASE. thank you to all those people who contributed i am greatly in your debt.
 
Hello, david3456777!

Since you've shown us nothing,
. . I assume you haven't got any of the answers (?)


My goal in school is to get to 1-100 only using four nines.

More information is required.

I assume we can use: \(\displaystyle +\;-\;\times\;\div\) and numbers like "99".
. . but can we use exponents, square roots, factorials, decimal points, etc. ?


\(\displaystyle \begin{array}{ccc} 1 &=& \frac{99}{99} \\ 2 &=& \frac{9}{9} + \frac{9}{9} \\ 3 &=& \frac{9+9+9}{9} \\ \vdots && \vdots \\ 10 &=& \frac{99-9}{9} \\ \vdots && \vdots \\ 100 &=& 99 + \frac{9}{9} \end{array}\)

 
hey my goal in school is to get to 1-100 only using four nines

and it's due TOMMOROW Your emergency is not ours.

somebody help me get to there The "help" you would receive should be the difference of efforts.
Or, put another way, it is what the answers are, minus your work shown.
So far 100% of the answers - 0% of the work from you = 100 % left of the work from you
still remaining.



and do it fast Again, read my first comment above. PLEASE.

thank you to
all those people who contributed You haven't contributed anything here so far.

i am greatly in your debt.Why should you be in any of our debt!? You can be thankful
when you earned the help first.


None of your laziness and mismanagement of time should be rewarded.



david3456777,

read what is at this link and attempt to follow it:


http://www.freemathhelp.com/forum/threads/41539-Read-Before-Posting!!
 
Last edited:
hey my goal in school is to get to 1-100 only using four nines and it's due TOMMOROW somebody help me get to there and do it fast PLEASE. thank you to all those people who contributed i am greatly in your debt.

0 = 99 - 99
1 = (9 - 9) + 9/9
2 = 9/9 + 9/9
3 = (9 + 9 + 9)/3
4 = 9/.9 - [(sqrt(9) + sqrt(9)]
5 = sqrt(9) + sqrt(9) - 9/9
6 = (9 - 9) + 9 - sqrt(9) = sqrt(9 + 9 + 9 + 9)
7 = sqrt(9) + sqrt(9) + 9/9
8 = 99/9 - sqrt(9) = 9 + 9 - 9/.9
9 = (9 - 9) + sqrt(9x9) = 9sqrt(9) - (9 + 9)
10 = (9 - 9) + 9/.9
11 = 9/.9 + 9/9 = 9 + (9 + 9)/9
12 = (9 - 9) + 9 + sqrt(9) = sqrt(9) + sqrt(9) + sqrt(9) + sqrt(9)
13 = 9 + sqrt(9) + 9/9
14 = 99/9 + sqrt(9)
15 = 9 + 9 - 9/sqrt(9)
16 = 9/9 + sqrt(9) + sqrt(9)
17 = 9 + 9 - 9/9
18 = 9 + 9 + (9 - 9)
19 = 9 + 9 + 9/9
20 = 9/.9 + 9/.9
21 = 9 + 9 = 9/sqrt(9)[FONT=&quot][/FONT]
 
0 = 99 - 99
1 = (9 - 9) + 9/9
2 = 9/9 + 9/9
3 = (9 + 9 + 9)/3 . . . . . Look at this again. Missing a "9" and can't have a "3."
4 = 9/.9 - [(sqrt(9) + sqrt(9)]
5 = sqrt(9) + sqrt(9) - 9/9
6 = (9 - 9) + 9 - sqrt(9) = sqrt(9 + 9 + 9 + 9)
7 = sqrt(9) + sqrt(9) + 9/9
8 = 99/9 - sqrt(9) = 9 + 9 - 9/.9
9 = (9 - 9) + sqrt(9x9) = 9sqrt(9) - (9 + 9)
10 = (9 - 9) + 9/.9
11 = 9/.9 + 9/9 = 9 + (9 + 9)/9
12 = (9 - 9) + 9 + sqrt(9) = sqrt(9) + sqrt(9) + sqrt(9) + sqrt(9)
13 = 9 + sqrt(9) + 9/9
14 = 99/9 + sqrt(9)
15 = 9 + 9 - 9/sqrt(9)
16 = 9/9 + sqrt(9) + sqrt(9) . . . . Look at this again. Missing a decimal point with the second "9."
17 = 9 + 9 - 9/9
18 = 9 + 9 + (9 - 9)
19 = 9 + 9 + 9/9
20 = 9/.9 + 9/.9
21 = 9 + 9 = 9/sqrt(9) . . . . Look at this again. The second equals sign must be a plus sign.



And still the OP has shown no work.
 
here are the numbers

hey so yesterday i got a ton but i still got a few here they are and thanks to all those people who answered.
38 41 42 43 44 46 47 49 50 52 56 58 59 61 62 64 65 67 66 68 70 74 76 86 88 92
here are the rest of the numbers i need.
 
And still the OP has shown no work.

Thanks ever so much for identifying my typos.

0 = 99 - 99
1 = (9 - 9) + 9/9
2 = 9/9 + 9/9
3 = (9 + 9 + 9)/9
4 = 9/.9 - [(sqrt(9) + sqrt(9)]
5 = sqrt(9) + sqrt(9) - 9/9
6 = (9 - 9) + 9 - sqrt(9) = sqrt(9 + 9 + 9 + 9)
7 = sqrt(9) + sqrt(9) + 9/9
8 = 99/9 - sqrt(9) = 9 + 9 - 9/.9
9 = (9 - 9) + sqrt(9x9) = 9sqrt(9) - (9 + 9)
10 = (9 - 9) + 9/.9
11 = 9/.9 + 9/9 = 9 + (9 + 9)/9
12 = (9 - 9) + 9 + sqrt(9) = sqrt(9) + sqrt(9) + sqrt(9) + sqrt(9)
13 = 9 + sqrt(9) + 9/9
14 = 99/9 + sqrt(9)
15 = 9 + 9 - 9/sqrt(9)
16 = 9/.9 + sqrt(9) + sqrt(9) 17 = 9 + 9 - 9/9
18 = 9 + 9 + (9 - 9)
19 = 9 + 9 + 9/9
20 = 9/.9 + 9/.9
21 = 9 + 9 + 9/sqrt(9)
 

A few more . . .


\(\displaystyle \begin{array}{c}(\sqrt{9})!(\sqrt{9})! + \sqrt{9} + \sqrt{9} \;=\;42 \\ \dfrac{9!}{((\sqrt{9})!)!(9+9)} \;=\;42 \\ (\sqrt{9})!(\sqrt{9})! + \dfrac{9}{.9} \;=\;46 \\ \dfrac{((\sqrt{9})!)!}{9} + 9 + \sqrt{9} \;=\;92 \end{array}\)


Can we use: /\(\displaystyle \log_{_{\sqrt{9}}}9 \,=\,2\,?\)
 
To quote "david".....


"HEY!"

Some of us (and I use that term loosely, because I would NOT give this lazy wretch even ONE answer!) have proved P. T. Barnum's famous quote....

There is INDEED a sucker born every minute.

And since this blatant beggar posted in the thread specified for questions in the HIGHEST level of math, for something that I've seen assigned to 8th graders, those who handed out answers should feel at least a little shame!
 
Now that the hockey-season finished.....


No no no no no....It is far from over. Having been born and raised in Los Angeles (though now living in Atlanta whose hockey team left for Winnipeg this year), I am beyond excited to see the Kings dominating! Maybe this is the year....FINALLY!!
 
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