Hi,

I've run into (another) difficulty in the chapter entitled 'further differentiation' in my book. Could anyone give me a pointer as to how to deal with the following problem?

A right circular cone with base radius r cm and height h cm has volume [tex]\frac{1}{3}\pi r^2h cm^3[/tex] and curved surface area [tex]\pi r (r^2 + h^2)^\frac{1}{2} cm^2[/tex]

Show that the curved surface area of the cone with volume [tex]\frac{4 \pi} {3} cm^3[/tex] is given by:

[tex]S^2 = \pi ^2(r^4 + \frac {16}{r^2})[/tex]

I can see no way in which these equations could be linked and am at a complete loss as to what to do here! It seems completely unlike anything covered in the book up till now so I'm completely lost.

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