jonnburton
Junior Member
- Joined
- Dec 16, 2012
- Messages
- 155
Hi,
I've run into (another) difficulty in the chapter entitled 'further differentiation' in my book. Could anyone give me a pointer as to how to deal with the following problem?
A right circular cone with base radius r cm and height h cm has volume \(\displaystyle \frac{1}{3}\pi r^2h cm^3\) and curved surface area \(\displaystyle \pi r (r^2 + h^2)^\frac{1}{2} cm^2\)
Show that the curved surface area of the cone with volume \(\displaystyle \frac{4 \pi} {3} cm^3\) is given by:
\(\displaystyle S^2 = \pi ^2(r^4 + \frac {16}{r^2})\)
I can see no way in which these equations could be linked and am at a complete loss as to what to do here! It seems completely unlike anything covered in the book up till now so I'm completely lost.
I've run into (another) difficulty in the chapter entitled 'further differentiation' in my book. Could anyone give me a pointer as to how to deal with the following problem?
A right circular cone with base radius r cm and height h cm has volume \(\displaystyle \frac{1}{3}\pi r^2h cm^3\) and curved surface area \(\displaystyle \pi r (r^2 + h^2)^\frac{1}{2} cm^2\)
Show that the curved surface area of the cone with volume \(\displaystyle \frac{4 \pi} {3} cm^3\) is given by:
\(\displaystyle S^2 = \pi ^2(r^4 + \frac {16}{r^2})\)
I can see no way in which these equations could be linked and am at a complete loss as to what to do here! It seems completely unlike anything covered in the book up till now so I'm completely lost.