Discussing Exponent Rules

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Gouskin

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For appropriate a, b, and c:

\(\displaystyle (a \cdot b)^c = a^cb^c\)

\(\displaystyle \dfrac{a^b}{a^c} = a^{b - c}\)

\(\displaystyle a^0 = 1, \ \ a \ne 0 \ \ and\)

\(\displaystyle 0^a = 0, \ \ a > 0\)

are some other exponent rules.

You just restated the same rules, though.
 
You just restated the same rules, though.
Gouskin, I (allegedly) "just restated" what "same rules?" Refer to what you mean by the post number in this thread. For one instance, \(\displaystyle \ (a \cdot b)^c = a^cb^c \ \) you claim is a restatement of what rule?
 
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Gouskin, I (allegedly) "just restated" what "same rules?" Refer to what you mean by the post number in this thread. For one instance, \(\displaystyle \ (a \cdot b)^c = a^cb^c \ \) you claim is a restatement of what rule?

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is a restatement of
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because
x/y = x*y^(-1)


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is the same as
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because
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.
This could only be true if they follow the rules of multiplicity.
And if they follow this rule, the exponent MUST be distributed throughout a multiplication of terms enclosed in parentheses.
 
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