Am I right in thinking that the term "1/x - 1/y" can be re-written to "y-x/xy"?
D davehogan New member Joined Sep 5, 2013 Messages 40 Sep 5, 2013 #1 Am I right in thinking that the term "1/x - 1/y" can be re-written to "y-x/xy"?
D Deleted member 4993 Guest Sep 5, 2013 #2 davehogan said: Am I right in thinking that the term "1/x - 1/y" can be re-written to "y-x/xy"? Click to expand... 1/x - 1/y → (y-x)/(xy) You must put the parentheses. Otherwise what you wrote → y-x/xy ← means: \(\displaystyle y - \frac{x}{x} * y\)
davehogan said: Am I right in thinking that the term "1/x - 1/y" can be re-written to "y-x/xy"? Click to expand... 1/x - 1/y → (y-x)/(xy) You must put the parentheses. Otherwise what you wrote → y-x/xy ← means: \(\displaystyle y - \frac{x}{x} * y\)
D davehogan New member Joined Sep 5, 2013 Messages 40 Sep 6, 2013 #3 Subhotosh Khan said: 1/x - 1/y → (y-x)/(xy) You must put the parentheses. Otherwise what you wrote → y-x/xy ← means: \(\displaystyle y - \frac{x}{x} * y\) Click to expand... Many thanks....(for answer and reminder).
Subhotosh Khan said: 1/x - 1/y → (y-x)/(xy) You must put the parentheses. Otherwise what you wrote → y-x/xy ← means: \(\displaystyle y - \frac{x}{x} * y\) Click to expand... Many thanks....(for answer and reminder).