hello, I've been having trouble with numerous questions similar to this one, so I was wondering if somebody could explain it step by step.
'Solve he equation: X^2/3 = 2X^1/3'
Now understand X^2/3 = Cube root( X)^2 and 2X^1/3 = cube root(2x)
My next line of thinking was to get rid of the cube roots, by cubing each side, so:
X^2 = 2X
Solving this to 0, I get X(X+2)=0
So X= 0 and X=-2
Substituting these values back into the equation, 0^2/3 = 2(0)^1/3 so 0 = 0, meaning 0 is a solution
However, I don't know I that answer was purely conidial as cube root (4) =Cube root (-4), when the answers are X = 0 and X = 8.
If anybody can explain where I have gone wrong, it would be greatly appreciated.
'Solve he equation: X^2/3 = 2X^1/3'
Now understand X^2/3 = Cube root( X)^2 and 2X^1/3 = cube root(2x)
My next line of thinking was to get rid of the cube roots, by cubing each side, so:
X^2 = 2X
Solving this to 0, I get X(X+2)=0
So X= 0 and X=-2
Substituting these values back into the equation, 0^2/3 = 2(0)^1/3 so 0 = 0, meaning 0 is a solution
However, I don't know I that answer was purely conidial as cube root (4) =Cube root (-4), when the answers are X = 0 and X = 8.
If anybody can explain where I have gone wrong, it would be greatly appreciated.